Determine the final temperature of water if 17.6 kJ of heat is added to 350 g of water initially at a temperature of 24.10 C. (specific heat of water is 4.184 Jg^-1K^-1)

To determine the final temperature of water after adding heat, we can use the equation:

q = m * c * ΔT

Where:
q is the heat added (in Joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in J/g°C)
ΔT is the change in temperature (in °C)

Given values:
q = 17.6 kJ = 17.6 * 10^3 J (since 1 kJ = 10^3 J)
m = 350 g
c = 4.184 J/g°C
Initial temperature, T1 = 24.10 °C

Now, let's rearrange the equation to solve for the change in temperature (ΔT):

ΔT = q / (m * c)

Substituting the given values:

ΔT = (17.6 * 10^3 J) / (350 g * 4.184 J/g°C)

Calculating ΔT:

ΔT = 12.5 °C

To find the final temperature, we add the change in temperature (ΔT) to the initial temperature (T1):

Final temperature = T1 + ΔT
Final temperature = 24.10 °C + 12.5 °C

Calculating the final temperature:

Final temperature = 36.60 °C

Therefore, the final temperature of the water after adding 17.6 kJ of heat is 36.60 °C.

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