Dale invested his savings in two investment funds. The $12,000 that he invested in Fund A returned a 1% profit. The amount that he invested in Fund B returned a 6% profit. How much did he invest in Fund B, if both funds together returned a 3% profit?

Thanks!!

Let's assume Dale invested amount x in Fund B.

The profit from Fund A can be calculated as 0.01 * $12,000 = $120.

The profit from Fund B can be calculated as 0.06 * x = 0.06x.

Together, the total profit from both funds is $120 + 0.06x.

The total investment amount is $12,000 + x.

Since the overall profit is 3%, it can be calculated as 0.03 * (total investment amount) = 0.03 * ($12,000 + x).

Now we can set up an equation:

$120 + 0.06x = 0.03 * ($12,000 + x).

Simplifying the equation:

$120 + 0.06x = $360 + 0.03x.

Subtracting 0.03x from both sides:

0.06x - 0.03x = $360 - $120.

0.03x = $240.

Dividing by 0.03:

x = $240 / 0.03.

x = $8,000.

Therefore, Dale invested $8,000 in Fund B.

To solve this problem, we can use a system of equations.

Let's assume Dale invested x dollars in Fund A and y dollars in Fund B.

According to the problem, the $12,000 invested in Fund A returned a 1% profit, which means Dale made 1% of $12,000 in profit.
Profit from Invested Amount in Fund A = 1% of $12,000 = 0.01 * $12,000 = $120

Similarly, the invested amount in Fund B returned a 6% profit, which means Dale made 6% of the amount he invested in Fund B.
Profit from Invested Amount in Fund B = 6% of y = 0.06 * y

Now, let's consider the total investment and total profit. The sum of the invested amounts in Fund A and Fund B should be $12,000.
x + y = $12,000

The total profit from both funds combined is 3% of the total investment.
Total Profit = 3% of ($12,000) = 0.03 * $12,000 = $360

From the information given, we can form the following equation:
Profit from Invested Amount in Fund A + Profit from Invested Amount in Fund B = Total Profit
$120 + 0.06y = $360

Now, we can solve the equation to find the value of y, which represents the amount Dale invested in Fund B.

$120 + 0.06y = $360
0.06y = $360 - $120
0.06y = $240
y = $240 / 0.06
y = $4000

Therefore, Dale invested $4000 in Fund B.

.01x + .06(12000-x) = .03(12000)

take over