Mass of iron cube having edge length 1.8m is 70g.Find it's density.
V = (1.8m)^3 = 5.83 m^3.
Density = 0.070kg/5.83m^3 = 0.012 kg/m^3.
To find the density of the iron cube, we need to use the equation:
Density = Mass ÷ Volume
The given information tells us the mass of the iron cube, which is 70g. However, we need to find the volume of the cube first. Since the cube has an edge length of 1.8m, we can calculate its volume using the formula:
Volume = (Edge Length)^3
Therefore, the volume of the iron cube is:
Volume = (1.8m)^3 = 5.832m^3
Now, we can substitute the values we have into the density equation:
Density = Mass ÷ Volume
Density = 70g ÷ 5.832m^3
However, it is important to ensure that the units of mass and volume are consistent. Since the mass given is in grams and the volume calculated is in cubic meters, let's convert the mass to kilograms:
1kg = 1000g
Therefore,
Mass = 70g ÷ 1000 = 0.07kg
Now we can substitute the values:
Density = 0.07kg ÷ 5.832m^3
Calculating the density gives us the result.