If 5 equal pieces of 25 ohm (omega) is joined in parallel then what is the equivalent resistance of it. Is it 5 or 1.please urgent
When a resistance wire having resistance R is cut into 5 equal parts, the resistance of each part becomes R/5 as resistance is directly proportional to length of the conductor or resistor;
So therefore the resistance of each of the five pieces will be 25/5=5 ohm
So,
Equivalent Resistance=1/5+1/5+1/5+1/5+1/5=5/5=1
Equivalent Resistance= 5ohm
When a resistance wire having resistance R is cut into 5 equal parts, the resistance of each part becomes R/5 as resistance is directly proportional to length of the conductor or resistor;
So therefore the resistance of each of the five pieces will be 25/5=5 ohm
So,
Equivalent Resistance=1/5+1/5+1/5+1/5+1/5=5/5=1
Equivalent Resistance= 1ohm
The resistance of each piece is still 25 ohms.
Now, if a single 25-ohm wire had been cut into five pieces, then each piece would have had a 5-ohm resistance. That is not what we have here.
think about it. The current has 5 different paths it can follow, so the resistance is 1/5 as great. So, 5 ohms
1/R = 1/25 + 1/25 + 1/25 + 1/25 + 1/25 = 5/25 = 1/5
So, R=5
Why would you think it is 1? Time to study some more.
To find the equivalent resistance of resistors connected in parallel, you can use the formula:
1 / Req = 1 / R1 + 1 / R2 + 1 / R3 + ...
In this case, since you have 5 equal resistors of 25 ohms each, the formula becomes:
1 / Req = 1 / 25 + 1 / 25 + 1 / 25 + 1 / 25 + 1 / 25
Simplifying this equation, you get:
1 / Req = 5 / 25
Next, flip both sides of the equation and simplify further:
Req = 25 / 5
Therefore, the equivalent resistance (Req) of the 5 equal resistors joined in parallel is 5 ohms.