y'and y''. y=x^1/2 ln(x)
y = √x lnx y' = lnx/(2√x) + 1/√x y" = 1/(2x^(3/2)) + lnx((-1/4)x^(-3/2)) + (-1/2)x^(-3/2) = -lnx/(4x^(3/2))
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