A bullet of mass 20g travelling at speed of 350m per second strike a steel plate at an angle of 30degree with the plane of plate it ricochets off at the same angle at a speed of 320m per second what is the magnitude of impulse that the steel plates gives to the projectile if the collision with with the plates take places over a time dt=10ki power -3s.what is average force exerted by the plateson the bullet
To find the magnitude of the impulse, we need to use the formula:
Impulse = Change in momentum
The initial momentum of the bullet can be calculated using:
P₁ = mass × initial velocity
Since the mass is given in grams, we need to convert it to kilograms:
mass = 20g = 0.02kg
Plugging in the values:
P₁ = 0.02kg × 350m/s
Now let's calculate the final momentum of the bullet:
P₂ = mass × final velocity
P₂ = 0.02kg × 320m/s
To find the change in momentum, we subtract the initial momentum from the final momentum:
change in momentum = P₂ - P₁
Next, we need to find the average force exerted by the plate on the bullet. The average force can be calculated using the formula:
Average force = Impulse / time
Given that the collision time is dt = 10^-3s, we can substitute these values into the formula.
Finally, once we have the magnitude of the impulse, we can find the average force exerted by the plate on the bullet.