What's the resulting solution if 2000cm3 of 1MH2S04 is mixed with 20cm3 of 1M NaOH? i got 0.5M,acidic in concentration.
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols H2SO4 = M x L = 1 x 2 = 2
mols NaOH = M x L = 1 x 0.02 = 0.02
All of the NaOH is used; it neutralizes 0.02 x 1/2 = 0.01 mols of H2SO4. That leaves how much H2SO4. That's 2-0.01 = 1.99
What's the volume? That's 2000 mL H2SO4 + 20 mL NaOH = 2020 mL total solution or 2.02 L.
M H2SO4 left = mols H2SO4/L solution = ?
To find the resulting solution after mixing 2000 cm3 of 1M H2SO4 with 20 cm3 of 1M NaOH, we need to perform a neutralization reaction between the acid (H2SO4) and the base (NaOH), which will yield a salt and water.
The balanced chemical equation for the neutralization reaction between H2SO4 and NaOH is as follows:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
First, we need to determine the limiting reactant, which is the reactant that is used up first. In this case, both H2SO4 and NaOH have equal concentrations of 1M, but the volumes are different. To compare the amounts of the reactants, we need to convert the volumes into moles.
The molar concentration (M) is defined as the number of moles of a substance dissolved in one liter (1000 cm3) of solution. Therefore, for H2SO4:
Number of moles of H2SO4 = Molarity × Volume (in liters)
= 1M × (2000 cm3 / 1000) L
= 2 moles
For NaOH:
Number of moles of NaOH = Molarity × Volume (in liters)
= 1M × (20 cm3 / 1000) L
= 0.02 moles
From the balanced chemical equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH. Since the number of moles of NaOH (0.02 moles) is less than half the number of moles of H2SO4 (2 moles), NaOH is the limiting reactant.
The limiting reactant determines the amount of product formed. Since NaOH is completely consumed, it reacts with all of the available H2SO4 in a 1:1 ratio. Therefore, the resulting solution will contain only Na2SO4 (sodium sulfate) and water.
Now, let's determine the concentration of the resulting solution by calculating the molar concentration of Na2SO4.
The total volume of the resulting solution can be obtained by adding the volumes of the reactants:
Total volume = 2000 cm3 + 20 cm3
= 2020 cm3
Since the limiting reactant is NaOH, the number of moles of Na2SO4 formed is equal to the number of moles of NaOH used, which is 0.02 moles.
The molar concentration of Na2SO4 can be calculated as:
Molarity = Number of moles / Volume (in liters)
= 0.02 moles / (2020 cm3 / 1000) L
≈ 0.01 M
So, the resulting solution after mixing 2000 cm3 of 1M H2SO4 with 20 cm3 of 1M NaOH is approximately 0.01M Na2SO4. This solution will be neutral in pH since the acid and base react completely to form a salt and water.