find the zigma of
1/2+2/3+3/4+....n/(n+1)
please show step help
that's sigma, not zigma.
Note that n/(n+1) = 1 - 1/(n+1)
So, the sum is the same as
n - Σ 1/(k+1)!
Unfortunately, this cannot be expressed using elementary functions.
1/2+2/3+3/4+....n/(n+1)
please show step help
Note that n/(n+1) = 1 - 1/(n+1)
So, the sum is the same as
n - Σ 1/(k+1)!
Unfortunately, this cannot be expressed using elementary functions.