what is the relative atomic mass of a silicon containing ore with 92% 28'Si,5%29'Si and 3%30'Si?
(0.92*28)+(0.05*29)+(0.03*30) = ?
28.11 i got this but 29 is the answer in my text.
To calculate the relative atomic mass of a silicon-containing ore with different isotopes, you need to consider the mass and abundance of each isotope.
1. Convert the percentages to decimals:
- 92% = 0.92
- 5% = 0.05
- 3% = 0.03
2. Find the atomic masses of each isotope:
- Mass of 28Si = 28
- Mass of 29Si = 29
- Mass of 30Si = 30
3. Multiply the atomic masses by their respective abundances:
- (28 * 0.92) + (29 * 0.05) + (30 * 0.03)
4. Calculate the sum:
- 25.76 + 1.45 + 0.90 = 28.11
Therefore, the relative atomic mass of the silicon-containing ore with 92% 28Si, 5% 29Si, and 3% 30Si is approximately 28.11.
To calculate the relative atomic mass of a silicon-containing ore with different isotopes, you need to multiply the isotopic mass of each isotope by its respective abundance, and then sum up the results.
In this case, the ore contains three isotopes of silicon: 28Si, 29Si, and 30Si, with abundances of 92%, 5%, and 3% respectively.
Here's how you can calculate the relative atomic mass:
1. Convert the abundance percentages to decimal form:
- 92% becomes 0.92
- 5% becomes 0.05
- 3% becomes 0.03
2. Multiply each isotope's abundance by its isotopic mass:
- For 28Si: 0.92 x 28 = 25.76
- For 29Si: 0.05 x 29 = 1.45
- For 30Si: 0.03 x 30 = 0.90
3. Add up the results:
- 25.76 + 1.45 + 0.90 = 28.11
Therefore, the relative atomic mass of the silicon-containing ore is approximately 28.11 atomic mass units (AMU).