what mass of h2o is formed when h2 reacts with 384g of o2?
humm
2H2 + O2 ---> 2H2O
O is 16 g/mol
so O2 is 32 grams/mol
so we have 384/32 = 12 mols of O2
That will yield 2*12 = 24 mols of H2O
a mol of H2O is 2+16 = 18 grams/mol
so 24 mols = 24*18 = 432 grams water
To determine the mass of H2O formed when H2 reacts with 384g of O2, we need to first balance the chemical equation for the reaction. The balanced equation for the reaction is:
2H2 + O2 -> 2H2O
From the balanced equation, we can see that 2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O.
To find the number of moles of O2, we can use its molar mass. The molar mass of O2 is approximately 32 g/mol.
Number of moles of O2 = mass of O2 / molar mass
Number of moles of O2 = 384g / 32 g/mol
Number of moles of O2 = 12 moles
Since the reaction ratio between H2 and O2 is 2:1, the moles of H2O formed will be half of the moles of O2 used.
Number of moles of H2O = 1/2 * number of moles of O2
Number of moles of H2O = 1/2 * 12 moles
Number of moles of H2O = 6 moles
Lastly, to find the mass of H2O formed, we can multiply the number of moles of H2O by its molar mass. The molar mass of H2O is approximately 18 g/mol.
Mass of H2O = number of moles of H2O * molar mass
Mass of H2O = 6 moles * 18 g/mol
Mass of H2O = 108 g
Therefore, when H2 reacts with 384g of O2, approximately 108g of H2O is formed.
To determine the mass of H2O formed when H2 reacts with 384g of O2, we need to use the balanced chemical equation for the reaction between H2 and O2:
2H2 + O2 -> 2H2O
According to the equation, 2 moles of H2 react with 1 mole of O2 to produce 2 moles of H2O.
First, we need to convert the mass of O2 to moles. We can use the molar mass of O2, which is 32 g/mol:
384g O2 * (1 mol O2 / 32 g O2) = 12 moles of O2
Next, we can use the mole ratio from the balanced equation to determine the moles of H2O formed.
From the balanced equation, we know that 2 moles of H2O are formed for every 1 mole of O2 reacted. Therefore, the moles of H2O formed from 12 moles of O2 would be:
12 moles O2 * (2 moles H2O / 1 mole O2) = 24 moles H2O
Finally, we need to convert the moles of H2O to grams. The molar mass of H2O is 18 g/mol:
24 moles H2O * (18 g H2O / 1 mol H2O) = 432 g H2O
Therefore, when H2 reacts with 384g of O2, it will form 432g of H2O.