For the reaction 2Na(s)+Cl2(g)→2NaCl(s)2Na(s)+Cl2(g)→2NaCl(s), how many grams of NaCl could be produced from 20 L of Cl2Cl2 (at STP)?
What, pray tell, is Cl2Cl2.
To find out how many grams of NaCl could be produced from 20 L of Cl2 (at STP), we need to use stoichiometry, which is a method used to calculate the amounts of reactants and products in a chemical reaction.
Step 1: Write down the balanced chemical equation:
2Na(s) + Cl2(g) → 2NaCl(s)
Step 2: Determine the molar ratio between Cl2 and NaCl:
From the balanced chemical equation, we can see that the molar ratio between Cl2 and NaCl is 1:2. This means that for every 1 mole of Cl2 reacted, 2 moles of NaCl are produced.
Step 3: Convert the volume of Cl2 (in L) to the amount in moles:
At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 L. Therefore, to convert 20 L of Cl2 to moles, we divide the volume by the molar volume:
20 L / 22.4 L/mol = 0.8928 moles of Cl2
Step 4: Use the mole ratio to determine the moles of NaCl:
Since the molar ratio between Cl2 and NaCl is 1:2, we multiply the moles of Cl2 by 2 to get the moles of NaCl:
0.8928 moles Cl2 × 2 moles NaCl/1 mole Cl2 = 1.7856 moles NaCl
Step 5: Calculate the mass of NaCl produced:
To calculate the mass of NaCl, we need to use its molar mass. The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl). Na has a molar mass of 22.99 g/mol, and Cl has a molar mass of 35.45 g/mol. Adding these together, we get:
22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Finally, to calculate the mass of NaCl produced, we multiply the moles of NaCl by its molar mass:
1.7856 moles NaCl × 58.44 g/mol = 104.5 grams
Therefore, approximately 104.5 grams of NaCl could be produced from 20 L of Cl2 (at STP).