Calculate the number of H Atoms present in 0.125 g CH3OH
mols CH3OH = grams/molar mass = ?
1 mol CH3OH contains 6.02E23 molecules.
Then there are 4x that number of H atoms..
To calculate the number of H atoms present in 0.125 g of CH3OH (methanol), follow these steps:
1. Determine the molar mass of CH3OH:
- C (carbon) has a molar mass of 12.01 g/mol.
- H (hydrogen) has a molar mass of 1.01 g/mol.
- O (oxygen) has a molar mass of 16.00 g/mol.
Add up the molar masses:
Molar Mass of CH3OH = (1 × 12.01 g/mol) + (4 × 1.01 g/mol) + (1 × 16.00 g/mol) = 32.04 g/mol.
2. Use the molar mass of CH3OH to convert grams to moles:
Moles of CH3OH = Mass (g) / Molar Mass (g/mol)
Moles of CH3OH = 0.125 g / 32.04 g/mol
3. Determine the mole ratio between the number of H atoms and moles of CH3OH:
- A molecule of CH3OH contains 4 hydrogen atoms.
- So, for every 1 mole of CH3OH, there are 4 moles of H atoms.
Therefore, the number of H atoms = Moles of CH3OH × 4
Now, let's calculate the number of H atoms:
Moles of CH3OH = 0.125 g / 32.04 g/mol ≈ 0.0039 mol
Number of H atoms = 0.0039 mol × 4 = 0.0156 mol
Hence, there are approximately 0.0156 moles of H atoms in 0.125 g of CH3OH.