A car drive straight of the edge of a cliff that is 54m high. The police note that the point of impact is 130m from the base of the cliff. How fast was the car travelling when it went off the cliff.
h = 0.5g*t^2.
54 = 4.9t^2, t = 3.32 s. = Fall time.
d = V*t, 130 = V*3.32, V = ?.
V in m/s.
To find the speed at which the car was traveling when it went off the cliff, we can use the principles of projectile motion.
The height of the cliff is given as 54m, and the horizontal distance from the base of the cliff to the point of impact is given as 130m.
First, let's find the time it takes for the car to fall from the cliff to the ground. We can use the equation for vertical displacement in free fall:
y = Vyt + (1/2)gt^2
where:
y = vertical displacement (height of the cliff) = -54m (negative because the car is falling)
Vy = vertical component of initial velocity = unknown
g = acceleration due to gravity = 9.8 m/s^2
t = time
Since the car starts at rest vertically, Vyt = 0, so the equation becomes:
-54 = (1/2)(9.8)t^2
Rearranging the equation:
t^2 = (-54 * 2) / 9.8
t^2 = -108 / 9.8
Solving for t:
t^2 ≈ -11.02
Here, we encounter a problem. The value of t^2 is negative, which means there is no real solution for time in this equation. This suggests that the equation does not accurately represent the problem.
Given this inconsistency, it is not possible to determine the speed of the car when it went off the cliff with the given information. There may be some additional details or data missing that would be required to solve the problem accurately.