A certain amount of gas occupy 5.0dm cube at 2atm.and 10 degree centigrade .calculate d number of mole present(R_0.082atm)
PV=nRT
n=PV/RT use the right R (units match what you have)
A certain amount of gas occupied 5.0dm at 2atm and 10°.calculate the number of mole present
a-certain-amount-of-gas-occupy-5.0dmcube-at-2atm-and-10-degree-centigrade-calculate- the number of moles present ( R=0.082atm dm^3
To calculate the number of moles present, we can use the ideal gas law equation, which is given by:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
First, we need to convert the given temperature from degrees Celsius to Kelvin by adding 273.15.
Given:
P = 2 atm
V = 5.0 dm^3 (which is equivalent to 5.0 L)
T = 10°C + 273.15 = 283.15 K
Substituting the given values into the ideal gas law equation:
(2 atm) * (5.0 L) = n * (0.0821 L·atm/(mol·K)) * (283.15 K)
Simplifying the equation:
10 atm·L = 23.07 L·atm·mol^-1·K^-1 * n * 283.15 K
Next, divide both sides of the equation by the product of the gas constant and temperature to isolate n:
10 atm·L / (23.07 L·atm·mol^-1·K^-1 * 283.15 K) = n
Finally, calculate the value of n:
n ≈ 0.00219 mol
Therefore, there are approximately 0.00219 moles of gas present in the given conditions.