a student walks 50m on a bearing 025 and then 200m due east.how far is she from her starting point
the student walked on a heading, not a bearing.
use the law of cosines. The distance d is found via
d^2 = 50^2 + 200^2 - 2*50*200*cos115°
draw the picture
Please show us the picture of the diagram
workings
working
The answer
This is not what we ask for na
Solution please
To find the distance from the starting point, we can use the Pythagorean theorem.
First, let's break down the student's movement into its components. The student walks 50m on a bearing of 025, which means she moves 50m in the northeast direction.
Using this information, we can calculate the distance she moves in the east direction and the distance she moves in the north direction.
Distance moved in the east direction = 200m
Distance moved in the north direction = 50m
Now, we have a right-angled triangle with the following sides:
Base = 200m (east)
Height = 50m (north)
Using the Pythagorean theorem, we can find the hypotenuse (distance from starting point) by finding the square root of the sum of the squares of the base and height.
Distance^2 = Base^2 + Height^2
Distance^2 = 200^2 + 50^2
Distance^2 = 40000 + 2500
Distance^2 = 42500
Now, square root both sides to find the distance:
Distance = √42500 ≈ 206.155m
Therefore, the student is approximately 206.155 meters away from her starting point.