In isosceles ΔABC, AC = BC, AB = 6 in,
CD ⊥ AB , and CD =√ 3 in. Find the perimeter of the isosceles triangle.
Can u plz put answer and equation
thanks, :)
The first answer is incorrect.
i am only in middle school and we are having to do this
Fuhkk
PLEASE TELL ME THE ANSWER SOMEONE
AC=BC = √(3+9) = √12
so, the perimeter is 6+2√12 or 6+4√3
I am also in middle school and am being forced to do this
To find the perimeter of the isosceles triangle, you need to determine the lengths of the remaining sides.
Let's denote the length of AC and BC as x. Since ΔABC is an isosceles triangle, we have AC = BC = x.
We're also given that AB = 6 in.
To find x, we can use the Pythagorean Theorem. In triangle ACD, CD is the perpendicular height dropped from the vertex of the right angle.
According to the Pythagorean Theorem, the sum of the squares of the lengths of the two legs of a right triangle (in this case, AC and CD) is equal to the square of the length of the hypotenuse (in this case, AD).
So we can set up the equation: x^2 = (AD)^2 = (CD)^2 + (AC)^2 = (√3)^2 + x^2
Simplifying the equation, we get: x^2 = 3 + x^2
This equation implies that 0 = 3, which is not possible. It seems there was an error in the information given, as it is not possible to have a triangle with these given lengths.
Please double-check the values provided and ensure they are accurate.