26.2g of sodium chloride(NaCL) are dissolved in enough water to make 100mL of solution. What is the molarity of this solution?

molarity=moles/liter=26.2/48 / .1

oops, redo molmass of NaCl, I have a typo.

To find the molarity of a solution, you need to know the amount of solute (in moles) and the volume of the solution (in liters).

First, we need to convert the given mass of sodium chloride (NaCl) to moles. To do this, we will use the molar mass of NaCl.

The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl):
Na = 22.99 g/mol
Cl = 35.45 g/mol

Molar mass NaCl = Na + Cl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Now, let's convert the mass of sodium chloride to moles:
moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 26.2 g / 58.44 g/mol = 0.448 mol

Next, we need to convert the volume of the solution from milliliters (mL) to liters (L):
volume of solution = 100 mL = 100/1000 L = 0.1 L

Finally, we can calculate the molarity of the solution using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity (M) = 0.448 mol / 0.1 L = 4.48 M

Therefore, the molarity of the solution is 4.48 M.