given two consecutive integers. The sum of three times the first integer and four times the second integer is 95. Find the integers
1 st integer = X.
2nd integer = x+1.
3x + 4(x+1) = 95. x = ?.
To solve this problem, we need to set up two equations based on the given information and then solve them simultaneously.
Let's assume that the first integer is "x". Since it is consecutive with the second integer, the second integer can be expressed as "x + 1".
According to the problem, the sum of three times the first integer and four times the second integer is 95. We can write this as an equation:
3x + 4(x + 1) = 95
Now, let's simplify this equation:
3x + 4x + 4 = 95
7x + 4 = 95
7x = 95 - 4
7x = 91
To solve for x, divide both sides of the equation by 7:
x = 91 / 7
x ≈ 13
So, the first integer is approximately 13. The second integer, which is consecutive to the first integer, can be found by adding 1:
x + 1 = 13 + 1 = 14
Therefore, the two consecutive integers are approximately 13 and 14.