At the movie theatre, child admission is $5.50 and adult admission is $9.50. On Saturday, 148 tickets were sold for a total sales of $1170.00. How many adult tickets were sold that day?

To solve this problem, we need to set up a system of equations based on the given information and then solve for the unknown variable.

Let's assume the number of child tickets sold is 'x' and the number of adult tickets sold is 'y'.

According to the given information, the child admission is $5.50, so the total cost of child tickets can be calculated as 5.50x.

Similarly, the adult admission is $9.50, so the total cost of adult tickets can be calculated as 9.50y.

The total number of tickets sold is given as 148, so we can write the equation:
x + y = 148

The total sales from the tickets is given as $1170.00, so we can write the equation:
5.50x + 9.50y = 1170.00

Now we can solve this system of equations to find the values of 'x' and 'y'.

Here is a step-by-step explanation of how to solve this system of equations using the substitution method:

1. Solve the first equation for one variable (x or y) in terms of the other variable.
x = 148 - y

2. Substitute this expression for x in the second equation.
5.50(148 - y) + 9.50y = 1170.00

3. Simplify and solve for y.
814.00 - 5.50y + 9.50y = 1170.00
4.00y = 356.00
y = 356.00 / 4.00
y = 89

Therefore, 89 adult tickets were sold on Saturday.

Let's assume the number of child tickets sold as C and the number of adult tickets sold as A.

1. We are given that the price of a child ticket is $5.50 and the price of an adult ticket is $9.50.
2. We are also given that a total of 148 tickets were sold and the total sales amounted to $1170.00.
3. Using the information above, we can set up a system of equations.

Equation 1: C + A = 148 (the total number of tickets sold is equal to 148)
Equation 2: 5.50C + 9.50A = 1170.00 (the total sales from the child and adult tickets is equal to $1170.00)

Now, we can solve this system of equations to find the number of adult tickets sold.

Let's solve Equation 1 for C:
C = 148 - A

Substitute this into Equation 2:
5.50(148 - A) + 9.50A = 1170.00

Expand and simplify:
814 - 5.50A + 9.50A = 1170.00
4.00A = 1170.00 - 814
4.00A = 356.00

Divide both sides by 4:
A = 356.00 / 4
A = 89

Therefore, 89 adult tickets were sold that day.

9.50a + 5.50(148-a) = 1170.00