The combustion of propane (C3H8) produces CO2 and H2O:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)
The reaction of 3.5 mol of O2 will produce ________ mol of H2O.
3.5 mols O2 x (4 mols H2O/5 mols O2) = 3.5 x 4/5 = ?
2.8
Well, the first thing we should do is calculate the number of moles of water (H2O) produced when 3.5 mol of oxygen (O2) reacts. According to the equation, for every 5 moles of oxygen, 4 moles of water are produced.
So, using a little math and proportion:
(4 mol H2O / 5 mol O2) x 3.5 mol O2 = 2.8 mol H2O
Therefore, 3.5 mol of O2 will produce 2.8 mol of H2O. Just be careful not to let those water molecules dampen your humor!
To determine the number of moles of H2O produced when 3.5 mol of O2 reacts, we can use the balanced chemical equation for the combustion of propane:
C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)
From the balanced equation, we can see that 5 moles of O2 produce 4 moles of H2O.
So, we can set up a proportion to find the number of moles of H2O produced:
(4 moles H2O) / (5 moles O2) = (x moles H2O) / (3.5 moles O2)
Cross-multiplying, we get:
4 moles H2O * 3.5 moles O2 = 5 moles O2 * x moles H2O
14 moles H2O = 5x
Dividing both sides by 5, we get:
14 moles H2O / 5 = x
x = 2.8 moles H2O
Therefore, the reaction of 3.5 mol of O2 will produce 2.8 mol of H2O.
To find the number of moles of H2O produced in the reaction, we can use the stoichiometry of the balanced equation. The stoichiometry tells us the ratio of moles between the reactants and products.
According to the balanced equation:
1 mol of C3H8 reacts with 5 mol of O2 to produce 4 mol of H2O.
Therefore, if we know the number of moles of O2, we can use the stoichiometric ratio to determine the number of moles of H2O produced.
Given that we have 3.5 moles of O2, we can set up a proportion using the stoichiometric ratio:
(3.5 mol O2 / 5 mol O2) = (x mol H2O / 4 mol H2O)
To solve for x (the number of moles of H2O), we can cross multiply:
3.5 mol O2 * 4 mol H2O = 5 mol O2 * x mol H2O
14 mol of H2O = 5 mol O2 * x mol H2O
Dividing both sides by 5 mol O2:
14 mol H2O / 5 mol O2 = x mol H2O
x = (14 mol H2O) / (5 mol O2)
x ≈ 2.8 mol
Therefore, the combustion of 3.5 mol of O2 will produce approximately 2.8 mol of H2O.