If one wanted to a make a 500.0 mL of 4.5 x 10-6M solution of this red dye, how many grams would they need to weigh out? The molar mass of the dye is 492 g/mol. SHOW WORK.
To calculate the mass of the red dye needed to make a 500.0 mL solution with a concentration of 4.5 x 10^(-6) M, we can follow the formula:
Mass (grams) = Concentration (M) x Molar mass (g/mol) x Volume (L)
First, let's convert the volume from mL to L. Since 1 L is equal to 1000 mL, we divide 500.0 mL by 1000 to get 0.500 L.
Now we can substitute the values into the formula:
Mass (grams) = (4.5 x 10^(-6) M) x (492 g/mol) x (0.500 L)
To simplify the calculation, let's multiply the concentration and molar mass together first:
(4.5 x 10^(-6) M) x (492 g/mol) = 2.214 x 10^(-3) g/L
Now, multiply this value by the volume:
Mass (grams) = (2.214 x 10^(-3) g/L) x (0.500 L)
Mass (grams) = 1.107 x 10^(-3) g
Therefore, to make a 500.0 mL solution of a concentration of 4.5 x 10^(-6) M, you would need to weigh out 1.107 x 10^(-3) grams of the red dye.
Please note that it is important to use proper safety precautions when working with chemicals and always double-check your calculations to ensure accuracy.