Find three consecutive odd integers such that the sum of 4 times the largest is -191

To find three consecutive odd integers, we can let the first integer be represented by x. The next two consecutive odd integers would then be x + 2 and x + 4.

According to the problem, the sum of 4 times the largest integer is -191. We can express this algebraically as 4(x + 4) = -191.

Now, let's solve this equation to find the value of x:

4(x + 4) = -191

We can distribute the 4 on the left side of the equation:

4x + 16 = -191

Next, we'll subtract 16 from both sides to isolate the variable:

4x = -191 - 16
4x = -207

Now, divide both sides of the equation by 4 to solve for x:

x = -207 / 4
x = -51.75

Since we are looking for odd integers, we need to round down x to the nearest whole number that is odd. Therefore, x would be -53.

Finally, we can find the three consecutive odd integers:

First odd integer: x = -53
Second odd integer: x + 2 = -53 + 2 = -51
Third odd integer: x + 4 = -53 + 4 = -49

So, the three consecutive odd integers that satisfy the conditions are -53, -51, and -49.

consecutive odd numbers are 2 apart

let the first be x
then the 2nd is x+2
and the third is x+4

"the sum of 4 times the largest is -191" makes no sense, "sum" is the result of addition , not multiplication

If you meant that the result of 4 times the largest is -191, then
4(x+4) = -191
4x + 16 = -191
4x = 197
x ≠ an integer,

your question is bogus, find the error