A cone-shaped container has a height of 9 in. and diameter of 2 in. It is filled with a liquid that is worth $2 per cubic inch.

What is the total value of the liquid in the container?

Use 3.14 for π .

Anyone who knows the answer are just willing to help .. help pleases

Someone

I think the answer 25.1 am i right

It might be 18.84

To find the total value of the liquid in the cone-shaped container, we first need to calculate the volume of the liquid and then multiply it by the cost per cubic inch.

The volume of a cone can be calculated using the formula:
V = (1/3) * π * r^2 * h

Given:
- Height (h) = 9 inches
- Diameter (d) = 2 inches

To find the radius (r) of the base, we divide the diameter by 2:
r = d/2 = 2/2 = 1 inch

Now, we can substitute the values into the formula:
V = (1/3) * 3.14 * (1 inch)^2 * 9 inches
V = (1/3) * 3.14 * 1 inch^2 * 9 inches
V = (1/3) * 3.14 * 1 * 9 cubic inches
V = 9.42 cubic inches

The total value of the liquid in the container can be found by multiplying the volume by the cost per cubic inch:
Value = V * $2 per cubic inch
Value = 9.42 cubic inches * $2 per cubic inch
Value = $18.84

Therefore, the total value of the liquid in the cone-shaped container is $18.84.