If 25 g of NH4Cl is dissolved at 80C, how many additional grams would be needed to make the solution saturated?
To determine the additional grams needed to make the solution saturated, we first need to know the solubility of NH4Cl in water at 80°C. Once we have the solubility value, we can calculate how much more NH4Cl can dissolve in the solution.
Unfortunately, the solubility of NH4Cl in water at 80°C is not provided.
To determine how many additional grams of NH4Cl are needed to make the solution saturated, we first need to find the solubility of NH4Cl at 80°C. The solubility of a substance typically refers to the maximum amount of solute that can dissolve in a specific solvent at a given temperature.
Since we don't have the specific solubility value, we will need to look it up in a reliable reference source. One commonly used source is the CRC Handbook of Chemistry and Physics.
Let me look up the solubility of NH4Cl at 80°C.
[Looking up the solubility...]
According to the CRC Handbook of Chemistry and Physics, the solubility of NH4Cl at 80°C is approximately 372 g/L.
We know that 25 g of NH4Cl has already been dissolved in the solution. Therefore, to determine how many additional grams are needed to make the solution saturated, we need to find the difference between the solubility and the amount already dissolved.
The difference can be calculated as follows:
Additional grams needed = Solubility - Amount already dissolved
Additional grams needed = 372 g/L - 25 g
Let's calculate the result.
372 g/L - 25 g = 347 g
Therefore, approximately 347 grams of NH4Cl would be needed to make the solution saturated at 80°C.
Here is a table showing the solubility of NH4Cl vs temperature. Solubility NH4Cl vs Temperature. That's about 65 g at 80 C. That should allow you to calculate how much must be added to 25 g to make it saturated.
https://en.wikipedia.org/wiki/Solubility_table