Complete and balance each of the following molecular reactions. Indicate the phase of each species. If no reaction occurs, write N.R.
A) ____ Na2CO3 (aq) + ___ Mg (NO3)2 (aq) -->
B)____ K2SO4(aq) + ___ Fe(CH3CO2)2 (aq) -->
C)___ AlCl3 (aq) +____ K2S (aq)
Please help and explain!!
To complete and balance the reactions, we will follow the following steps:
Step 1: Write the chemical formula for each compound involved in the reaction.
Step 2: Identify the elements present and determine their charges.
Step 3: Use these charges to balance the charges in the compound formed.
Step 4: Balance the atoms by adjusting the coefficients.
Let's start with reaction A):
A) Na2CO3 (aq) + Mg(NO3)2 (aq) -->
Step 1: The chemical formulas for the compounds are:
Na2CO3: Sodium carbonate
Mg(NO3)2: Magnesium nitrate
Step 2: We need to determine the charges of the elements involved. The charges can be found from the periodic table. Sodium (Na) has a charge of +1, carbonate (CO3) has a charge of -2, magnesium (Mg) has a charge of +2, and nitrate (NO3) has a charge of -1.
Step 3: To balance the charges, we need two sodium ions to balance one carbonate ion and one magnesium ion to balance two nitrate ions.
Step 4: The balanced reaction is:
Na2CO3 (aq) + Mg(NO3)2 (aq) --> 2 NaNO3 (aq) + MgCO3 (s)
Now, let's move on to reaction B):
B) K2SO4 (aq) + Fe(CH3CO2)2 (aq) -->
Step 1: The chemical formulas for the compounds are:
K2SO4: Potassium sulfate
Fe(CH3CO2)2: Iron(II) acetate
Step 2: We need to determine the charges of the elements involved. Potassium (K) has a charge of +1, sulfate (SO4) has a charge of -2, iron (Fe) has a charge of +2, and acetate (CH3CO2) has a charge of -1.
Step 3: To balance the charges, we need two potassium ions to balance one sulfate ion and one iron ion to balance two acetate ions.
Step 4: The balanced reaction is:
K2SO4 (aq) + Fe(CH3CO2)2 (aq) --> 2 KCH3CO2 (aq) + FeSO4 (s)
Now, let's move on to reaction C):
C) AlCl3 (aq) + K2S (aq) -->
Step 1: The chemical formulas for the compounds are:
AlCl3: Aluminum chloride
K2S: Potassium sulfide
Step 2: We need to determine the charges of the elements involved. Aluminum (Al) has a charge of +3, chloride (Cl) has a charge of -1, potassium (K) has a charge of +1, and sulfide (S) has a charge of -2.
Step 3: To balance the charges, we need three potassium ions to balance one aluminum ion and two chloride ions to balance one sulfide ion.
Step 4: The balanced reaction is:
AlCl3 (aq) + 3 K2S (aq) --> 3 KCl (aq) + Al2S3 (s)
Note: The state of each species is indicated by (aq) for aqueous and (s) for solid. If no reaction occurs, it would be indicated as "N.R" (No Reaction).
To balance each of the molecular reactions and indicate the phase of each species, you need to follow these steps:
A) Na2CO3 (aq) + Mg(NO3)2 (aq) -->
First, let's identify the elements and compounds involved in the reaction. We have sodium carbonate (Na2CO3) and magnesium nitrate (Mg(NO3)2).
Next, we need to balance the equation. Start by identifying the elements that are unbalanced. In this case, we have Na and Mg.
Na: There are two Na atoms on the left side, so we need to put a coefficient of 2 in front of Na2CO3:
2 Na2CO3 (aq) + Mg(NO3)2 (aq) -->
Mg: There is one Mg atom on the right side, so we also need a coefficient of 2 in front of Mg(NO3)2:
2 Na2CO3 (aq) + 2 Mg(NO3)2 (aq) -->
Now, check if the elements are balanced. We have:
4 Na atoms on the left (2 Na2CO3 x 2 Na)
2 Mg atoms on the right (2 Mg(NO3)2 x 1 Mg)
The equation is balanced in terms of atoms. Lastly, to indicate the phase, "(aq)" means aqueous (dissolved in water).
Therefore, the balanced equation is:
2 Na2CO3 (aq) + 2 Mg(NO3)2 (aq) -->
B) K2SO4 (aq) + Fe(CH3CO2)2 (aq) -->
Similarly, we have potassium sulfate (K2SO4) and iron(II) acetate (Fe(CH3CO2)2).
Start by balancing potassium (K) and iron (Fe) atoms.
K: There are two K atoms on the left side, so we put a coefficient of 2 in front of K2SO4:
2 K2SO4 (aq) + Fe(CH3CO2)2 (aq) -->
Fe: There is one Fe atom on the right side. We need a coefficient of 2 in front of Fe(CH3CO2)2:
2 K2SO4 (aq) + 2 Fe(CH3CO2)2 (aq) -->
Check if the elements are balanced:
4 K atoms on the left (2 K2SO4 x 2 K)
2 Fe atoms on the right (2 Fe(CH3CO2)2 x 1 Fe)
The equation is balanced in terms of atoms. "(aq)" represents aqueous.
The balanced equation is:
2 K2SO4 (aq) + 2 Fe(CH3CO2)2 (aq) -->
C) AlCl3 (aq) + K2S(aq) -->
Here we have aluminum chloride (AlCl3) and potassium sulfide (K2S).
Start by balancing aluminum (Al) and sulfur (S) atoms.
Al: There is one Al atom on the left side, so no coefficient is needed for AlCl3.
AlCl3 (aq) + K2S (aq) -->
S: There is one S atom on the right side. No coefficient is needed for K2S.
AlCl3 (aq) + K2S (aq) -->
The equation is already balanced in terms of atoms. "(aq)" represents aqueous.
The balanced equation is:
AlCl3 (aq) + K2S (aq)