If the heat of 110J is added to a gaseous system, change in internal energy is 40J, then the amount of external work done is?
Work=Heat - internal energy
W=A-U
To calculate the amount of external work done in a gaseous system, we need to use the First Law of Thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat added (Q) minus the work done (W) by the system:
ΔU = Q - W
In this case, we are given that the heat added to the system is 110J (Q = 110J) and the change in internal energy is 40J (ΔU = 40J).
Using the first law of thermodynamics equation, we can rearrange it to solve for the work done:
W = Q - ΔU
W = 110J - 40J
W = 70J
Therefore, the amount of external work done on the gaseous system is 70J.