9.0/1 points | Previous Answers SSTCalc6 2.3.046.My Notes
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Let
f(x) =
4x2 if x > 2
4x + 3 if x ≤ 2.
Show that f is continuous from the left at
x = 2,
but not from the right.
lim f(x) =
n→2−
f(2) =
lim f(x) =
n→2+
4x+3 = 11 at x=2
4x^2 = 16 at x=2
Since f(x) = 4x+3 for x <= 2, lim(x->2-) f(x) = 11 = f(2)
But lim(x->2+) = 16 ≠ 11