Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00 x 10-7 m (about one hundredth of the thickness of a sheet of paper). Find the area of such a sheet that can be formed from 3.70 kg of silver.
To find the area of a silver sheet that can be formed from a given mass of silver, we need to use the density of silver and the thickness of the sheet.
The density of silver is 10.5 g/cm³ (or 10500 kg/m³).
The thickness of the sheet is 3.00 x 10⁻⁷ m.
First, let's convert the mass of silver to grams:
3.70 kg = 3.70 x 1000 g = 3700 g
Next, we can calculate the volume of the silver sheet using the formula:
Volume = mass / density
Volume = 3700 g / 10500 kg/m³ = 0.352381 m³
Finally, we can calculate the area of the silver sheet using the formula:
Area = Volume / thickness
Area = 0.352381 m³ / (3.00 x 10⁻⁷ m) = 1.174603 x 10⁶ m²
Therefore, the area of the silver sheet that can be formed from 3.70 kg of silver is approximately 1.174603 x 10⁶ square meters.
To find the area of the silver sheet, we can use the formula:
Area = (mass / density) / thickness
Given:
Mass of silver = 3.70 kg
Thickness of sheet = 3.00 x 10^-7 m
The density of silver is approximately 10,490 kg/m^3.
Substituting the values into the formula:
Area = (3.70 kg / 10,490 kg/m^3) / (3.00 x 10^-7 m)
Calculating the area:
Area ≈ (0.000352 m^3) / (3.00 x 10^-7 m)
≈ 1.17333 x 10^6 m^2.
Therefore, the area of the silver sheet that can be formed from 3.70 kg of silver is approximately 1.17333 x 10^6 square meters.
1.) Look up the density of Silver which is: 10.5 * 10^3 kg/m^3
2.) Now find Volume using the formula Density = Mass/Volume. You should get 3.52 * 10^-4 m^3
3.) The Volume of such a sheet is simply (thickness * area). V=l*A
4.) We already know Volume (3.52*10^-4 m^3) and thickness (3*10^-7m).
5.) So the area of this sheet should be: A=V/l = 1,174.6 m^2