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If cscØ = 4/3, find sinØ + sinØ cot^2 Ø
1 answer
well,
sinØ = 3/4
cosØ = √5/4
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What is the first step. Explain please.
Which expression is equivalent to cos^2x + cot^2x + sin2^x? a) 2csc^2x b) tan^2x c)
what is the value of cot 2π/5?
how do i find the answer?
sinØ (1+ tanØ) + cosØ(1+ cotØ) = (secØ + cosecØ)
how do you solve this problem?
1+sinØ/cosØ +cosØ/1+sinØ = 2secØ and cosß- cosß/1-tanß = sinßcosß/sinß-cosß
Use implicit differentiation to show
dy/dx = [(1-xy)cot(y)]/[x^2 cot(y) + xcsc^2(y)] if xy = ln(x cot y).
If cscØ = 4/3, find sinØ + sinØ cot^2 Ø
As the answer to:
(tanØ * cosØ/ sinØ) + cotØ * sinØ * tanØ* cscØ I got 2, is that correct?
How can I prove this identity?
(1 + sinØ + cosØ):(1 - sinØ + cosØ) = (1 + sinØ) : cosØ
1. The expression sinπ is equal to 0, while the expression 1/cscπ is undefined. Why is sinø=1/cscø still an identity?
2.
Prove the following:
1/(tanØ - secØ ) + 1/(tanØ + secØ) = -2tanØ (1 - sinØ)/(1 + sinØ) = sec^2Ø - 2secØtanØ + tan^2Ø