Three cubic meters of liquid nitrogen has a mass about 2700 kg. When this much liquid nitrogen evaporates into gaseous air of density 1.25 kg/m3, what will its volume be? Show your work
2700 kg * 1m^3/1.25kg = 2160 m^3
To find the volume of the evaporated liquid nitrogen, we need to use the concept of density. Density is defined as mass divided by volume (ρ = m/V).
Given that the initial mass of the liquid nitrogen is 2700 kg and its volume is 3 cubic meters, we can calculate its initial density as follows:
Density of liquid nitrogen = Mass of liquid nitrogen / Volume of liquid nitrogen
ρ1 = 2700 kg / 3 m^3
Now, we are provided with the density of the gaseous air, which is 1.25 kg/m^3. Let's denote the final volume of the evaporated nitrogen as V2, and since the density is given, we can write:
Density of gaseous air = Mass of evaporated nitrogen / Volume of evaporated nitrogen
1.25 kg/m^3 = 2700 kg / V2
Next, we can rearrange this equation to find the volume of the evaporated nitrogen:
V2 = 2700 kg / 1.25 kg/m^3
V2 = 2160 m^3
Therefore, when the liquid nitrogen evaporates into gaseous air of density 1.25 kg/m^3, its volume will be 2160 cubic meters.