a photograph has an area of 80sq inches.the length of the photo is 1 1/4 width. what is the following dimension of the photgraph?
To find the dimensions of the photograph, we need to set up an equation using the given information.
Let's assume the width of the photograph is x inches. According to the given information, the length of the photograph is 1 1/4 times the width, or 1.25x inches.
We know that the area of a rectangle is equal to the length multiplied by the width. So, we can set up the equation:
Area = Length × Width
Substituting the given values:
80 sq inches = 1.25x inches × x inches
To solve this equation, we need to simplify it and then solve for x.
Multiply the length and width:
80 sq inches = 1.25x^2 inches^2
Now divide both sides by 1.25 to isolate x^2:
(80 sq inches) / 1.25 = (1.25x^2 inches^2) / 1.25
64 sq inches = x^2 inches^2
To remove the square from the equation, we need to take the square root of both sides:
√(64 sq inches) = √(x^2 inches^2)
Simplifying:
8 inches = x inches
Therefore, the width of the photograph is 8 inches. The length can be found by multiplying the width by 1 1/4:
Length = 1.25 × Width
Length = 1.25 × 8 inches
Length = 10 inches
So, the dimensions of the photograph are 8 inches by 10 inches.