An Effort Of 250N Raises A Load Of 1000N Through 5m In A Pulley System.If The Effort Moves 30m,what Is; (a)the Work Done In Raising The Load (b)the Work Done By The Effort (c)the Efficiency
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To find the work done, we can use the formula:
Work = Force x Distance
(a) The work done in raising the load can be found by multiplying the force (load) by the distance it was raised:
Work(load) = Force(load) x Distance
= 1000N x 5m
= 5000 Joules
So, the work done in raising the load is 5000 Joules.
(b) The work done by the effort can be found by multiplying the force (effort) by the distance it moved:
Work(effort) = Force(effort) x Distance
= 250N x 30m
= 7500 Joules
So, the work done by the effort is 7500 Joules.
(c) Efficiency is defined as the ratio of useful work done by a machine or system to the total work input. In this case, the useful work done by the machine is the work done in raising the load. The total work input is the work done by the effort. Therefore, the efficiency can be calculated as:
Efficiency = (Useful Work / Total Work) x 100%
Efficiency = (5000 Joules / 7500 Joules) x 100%
= 0.67 x 100%
= 67%
So, the efficiency of the pulley system is 67%.