The amount of oil used by a ship traveling at a uniform speed varies jointly with the distance and the square of the speed. The ship uses 30 barrels of oil in traveling 85 miles at 42 mi/h. How many barrels of oil are used when the ship travels 26 miles at 54 mi/h? Round your answer to the nearest tenth of a barrel, if necessary.
2.3
15.2
49.6
9.2
My answer is 15.2 barrels
1. C) 16
2. C) y = 6x / z ; 18
3. C) You can double check with mathway
4. D) ^^
5. A) x = -3; x = 1
6. D) asymptote: x = 3; hole: x = -3
7. D) There is no horizontal asymptote.
8. A) Look to 3
9. B) 15.2 barrels
10. D) nt = 440
11. C) 87.7 mL
Oil=m*distance*speed^2
30=m*85* 42
m=30/85*42^2
barrels=m*d*speed^2
barrels=(30/(84*42^2)) * 26*54^2
I get 15.2 also
30 * (54/42)^2 * (26/85)
@tea is 100% right thank u sm
thank you
tysm tea
To determine the amount of oil used by the ship when traveling 26 miles at 54 mi/h, we can use the joint variation equation.
First, let's set up the equation using the given values in the problem:
Oil used = k * distance * speed^2
We are given that the ship uses 30 barrels of oil when traveling 85 miles at 42 mi/h. Let's use these values to find the constant of variation, k.
30 = k * 85 * (42)^2
Solving for k, we divide both sides by (85 * 42^2):
k = 30 / (85 * 42^2)
Now that we have the constant of variation, we can use it to find the amount of oil used when the ship travels 26 miles at 54 mi/h:
Oil used = k * distance * speed^2
= (30 / (85 * 42^2)) * 26 * (54)^2
Calculating this expression will give us the amount of oil used in barrels. Rounding to the nearest tenth of a barrel, we find that the answer is 9.2 barrels.
Therefore, the correct answer is 9.2 barrels, not 15.2 barrels.