What volume of copper (
density 8.96 g/cm3
)
would be needed to balance a 1.15 cm3 sample of lead (
density 11.4 g/cm3
)
on a two-pan laboratory balance?
mass = density * volume, so since the two masses must be equal, the volume v we want is found by
8.96v = 11.4*1.15
4.15
To balance the samples on a two-pan laboratory balance, we need to calculate the volume of copper required to balance the 1.15 cm3 sample of lead.
First, let's determine the mass of the lead sample:
Mass of lead (m1) = Density of lead (d1) * Volume of lead (v1)
= 11.4 g/cm3 * 1.15 cm3
= 13.11 g
Since copper has a different density, we need to calculate the volume of copper that would have the same mass as the lead sample.
Let's use the formula for density:
Density (d) = Mass (m) / Volume (v)
Rearranging the formula to solve for volume:
Volume (v) = Mass (m) / Density (d)
Now, substitute the known values for copper density and the mass of the lead sample:
Volume of copper (v2) = Mass of lead (m1) / Density of copper (d2)
= 13.11 g / 8.96 g/cm3
≈ 1.46 cm3
Therefore, to balance the 1.15 cm3 sample of lead, we would need approximately 1.46 cm3 of copper.
To find the volume of copper needed to balance the lead sample on a two-pan laboratory balance, you first need to understand the principle of balancing masses.
The principle of balancing masses on a two-pan balance states that the mass on one side of the balance is equal to the mass on the other side. In this case, the lead sample has a volume of 1.15 cm^3 and a density of 11.4 g/cm^3. To find the mass of the lead sample, you can multiply its volume by its density:
Mass of lead = Volume of lead x Density of lead
Mass of lead = 1.15 cm^3 x 11.4 g/cm^3
Now, to balance the lead sample, you need to find an equal mass of copper. Since the density of copper is given as 8.96 g/cm^3, you can calculate the volume of copper needed using the following formula:
Volume of copper = Mass of lead / Density of copper
Let's plug in the values:
Volume of copper = (1.15 cm^3 x 11.4 g/cm^3) / 8.96 g/cm^3
By performing the calculation, you will find the volume of copper needed to balance the lead sample on the two-pan laboratory balance.