phobos, a moon of mars has maas of 1.08 x 10^16 kg, and an average radius of 1.35x10^4 m. calculate the gravitational field strength at the surface of phobos
F = G Mm m /Rm^2
F/m = G Mm/Rm^2
= 6.67×10-11 m^3 kg-1 s-2 * 1.08*10^16kg/[1.35*10^4]^2m^2
500
Why did the moon go to therapy? Because it felt a little spaced out! Now, let's calculate the gravitational field strength at the surface of Phobos.
We can use the formula for gravitational field strength, which is given by g = (G * m) / r^2, where G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m is the mass of the object, and r is the distance from the center of the object.
Plugging in the values for Phobos, we get:
g = (6.67 x 10^-11 N*m^2/kg^2 * 1.08 x 10^16 kg) / (1.35 x 10^4 m)^2
Calculating this, we find the gravitational field strength at the surface of Phobos is approximately 0.039 m/s^2.
So, the answer is 0.039 m/s^2. Don't let Phobos' small size fool you, it still has some gravity tricks up its sleeve!
To calculate the gravitational field strength at the surface of Phobos, you can use the formula for gravitational field strength:
g = G * (m / r^2)
Where:
g is the gravitational field strength
G is the gravitational constant (approximated as 6.674 x 10^-11 N(m/kg)^2)
m is the mass of Phobos
r is the average radius of Phobos
Plugging in the given values:
m = 1.08 x 10^16 kg
r = 1.35 x 10^4 m
G = 6.674 x 10^-11 N(m/kg)^2
Let's calculate the gravitational field strength at the surface of Phobos step-by-step:
Step 1: Square the radius of Phobos
r^2 = (1.35 x 10^4 m)^2 = 1.8225 x 10^8 m^2
Step 2: Divide the mass of Phobos by the square of its radius
m / r^2 = (1.08 x 10^16 kg) / (1.8225 x 10^8 m^2) = 5.9312 x 10^7 kg/m
Step 3: Multiply the result by the gravitational constant
g = (6.674 x 10^-11 N(m/kg)^2) * (5.9312 x 10^7 kg/m)
g = 3.9589 x 10^-3 N/kg
Therefore, the gravitational field strength at the surface of Phobos is approximately 3.9589 x 10^-3 N/kg.
To calculate the gravitational field strength at the surface of Phobos, you can use the formula:
g = (G * M) / r^2
Where:
g is the gravitational field strength
G is the universal gravitational constant (approximately 6.67430 x 10^-11 N*(m/kg)^2)
M is the mass of Phobos
r is the radius of Phobos
Let's plug in the values:
M = 1.08 x 10^16 kg
r = 1.35 x 10^4 m
g = (6.67430 x 10^-11 N*(m/kg)^2 * (1.08 x 10^16 kg)) / (1.35 x 10^4 m)^2
Now, let's calculate it step by step:
Step 1: Calculate the square of the radius: (1.35 x 10^4 m)^2 = 1.8225 x 10^8 m^2
Step 2: Calculate the gravitational field strength:
g = (6.67430 x 10^-11 N*(m/kg)^2 * (1.08 x 10^16 kg)) / (1.8225 x 10^8 m^2)
Now, let's multiply these values:
g = 0.089 N/kg
Therefore, the gravitational field strength at the surface of Phobos is approximately 0.089 N/kg.