An electron starts from rest travels a distance of 15 cm with constant acceleration and hits a television screen at a speed of 3×10^6 m/s .Calculate the acceleration of the electron.
Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop. She drops a wooden block with a mass of 0.5 kilograms on a sensor on the floor. The sensor measures the force of the impact as 4.9 newtons. What’s the acceleration of the wooden block when it hits the sensor?
yeezus
ratio
To calculate the acceleration of the electron, we can use the following formula:
v^2 = u^2 + 2as
where:
v = final velocity (3×10^6 m/s)
u = initial velocity (0 m/s, as the electron starts from rest)
a = acceleration (unknown)
s = distance traveled (15 cm = 0.15 m)
Let's plug in the values and solve for a:
(3×10^6 m/s)^2 = (0 m/s)^2 + 2a(0.15 m)
(9×10^12 m^2/s^2) = 0 + (0.3a)
Dividing both sides of the equation by 0.3 gives us:
a = (9×10^12 m^2/s^2) / 0.3
a ≈ 3×10^13 m^2/s^2
Therefore, the acceleration of the electron is approximately 3×10^13 m^2/s^2.
1. V^2 = Vo^2 + 2a*d.
(3*10^6)^2 = 0 + 2a*0.15, a = ?.
2. F = M*a, a = F/M = 4.9/0.5 =