A car was travelling at the speed of 20m/s when the driver saw a cat on the road 40 m away. He step on the brake and the car came into a halt after 6 seconds. How far did the car travel. What will happen to the cat?
avg speed slowing down=20/2=10
distance to stop=avgspeed*time=10*6
the cat is kuput.
To find out how far did the car travel, we can use the equation:
distance = initial velocity × time + 0.5 × acceleration × time^2
Given:
- Initial velocity (u) = 20 m/s
- Time (t) = 6 seconds
Since the car came to a halt, the final velocity (v) is 0 m/s. Thus, acceleration (a) can be calculated using the equation:
v = u + at
Rearranging the equation, we get:
a = (v - u) / t
Substituting the given values, we have:
a = (0 - 20) / 6
a = -20 / 6
a = -3.33 m/s^2 (rounded to two decimal places)
Now we can find the distance traveled by the car:
distance = initial velocity × time + 0.5 × acceleration × time^2
distance = (20 × 6) + 0.5 × (-3.33) × (6)^2
distance = 120 + (-3.33) × 36
distance = 120 + (-119.88)
distance = 0.12 meters
Therefore, the car traveled a distance of approximately 0.12 meters.
Regarding the cat, assuming it did not move from its initial position, it would be hit by the car. However, if the cat had time to react and move out of the car's path, it would not be hit.
To calculate the distance the car traveled, we need to use the equation of motion: distance = initial velocity * time + 0.5 * acceleration * time^2. In this case, since the car came to a halt, the final velocity is 0 m/s.
Given:
Initial velocity (u) = 20 m/s
Final velocity (v) = 0 m/s
Time (t) = 6 seconds
Using the equation of motion, we can rearrange it to solve for distance:
distance = (initial velocity * time) + (0.5 * acceleration * time^2)
Since the car comes to a halt, the acceleration will be the negative deceleration caused by the braking. Assuming constant deceleration, we can find it using the equation: acceleration = (final velocity - initial velocity) / time.
By substituting the given values into these equations, we can find the distance the car traveled.
acceleration = (final velocity - initial velocity) / time
acceleration = (0 - 20) / 6
acceleration = -20 / 6
acceleration = -3.33 m/s^2 (rounded to two decimal places)
distance = (initial velocity * time) + (0.5 * acceleration * time^2)
distance = (20 * 6) + (0.5 * -3.33 * 6^2)
distance = 120 + (0.5 * -3.33 * 36)
distance = 120 + (-3.33 * 18)
distance = 120 + (-59.94)
distance = 60.06 meters
So, the car traveled a distance of 60.06 meters.
As for the cat, based on the information given, we cannot determine its fate with certainty. It will mostly depend on the reaction time and movements of the cat, as well as the braking capabilities of the car. In general, it is crucial to drive safely and be vigilant to avoid accidents involving animals on the road.