Find the equation of the line that passes through the points (1,4) and (2,-8).

Question options:

y = -3x + 9


y = 6x + 5


y = -12x + 16


y = 12x - 8 < this one is wrong..

I thought I had it right so how do I find the correct answer? i'm not getting any of the other answer choices.

slope= (4+8)/(1-2)=-12

y=-12x+b
now put in either point into that .lets do the 1,4
4=-12*1+b
B=16
y=-12x+16

Oops. You missed my typo. The slope is -12.

y-4 = -12(x-1)
y = -12x + 16

Thanks Mr.Bob & Mr. Steve.. AGAIN.

I honestly need to practice this more obviously but 4 more months till graduation and everyone on here has been helping me since the 9th grade so it's a huge thank you.

To find the equation of the line that passes through the points (1,4) and (2,-8), we can use the point-slope form of a linear equation:

y - y1 = m(x - x1),

where (x1, y1) is one point on the line and m is the slope of the line.

First, let's calculate the slope (m) using the coordinates of the two points:
m = (y2 - y1) / (x2 - x1),

where (x1, y1) = (1, 4) and (x2, y2) = (2, -8):

m = (-8 - 4) / (2 - 1) = -12 / 1 = -12.

Now, we have the slope (m = -12) and one point on the line (x1, y1) = (1, 4), so we can substitute these values into the point-slope form:

y - 4 = -12(x - 1).

Next, we simplify the equation:

y - 4 = -12x + 12.

To obtain the equation in slope-intercept form (y = mx + b), we isolate y:

y = -12x + 12 + 4.

y = -12x + 16.

Therefore, the correct equation of the line that passes through the points (1,4) and (2,-8) is y = -12x + 16.

Out of the given answer choices, the correct one is y = -12x + 16.