Find the slope of the line that contains the two points (3,2) and (1,-4).
m = - 3
m = - 1/3 <-- ?
m = 3
m = 1/3
Find the slope of the line that contains the points (-2, 4) and (-4, 6).
m = -1
m = 1 <--
m = - 1/3
m = 1/3
Find the equation of the line that passes through the points (7,4) and (-5,-2)?
y=1/2x-1/2
y=-1/2x-1/2
y=-1/2x+1/2<--
y=1/2x+1/2
Find the equation of the line that passes through the points (1,4) and (2,-8).
y = -3x + 9
y = 6x + 5
y = -12x + 16
y = 12x - 8 <---
Find the slope of the line that contains the two points (3,2) and (1,-4).
slope is ∆y/∆x = (-4-2)/(1-3) = -6/-2 = 3
Find the slope of the line that contains the points (-2, 4) and (-4, 6)
slope is (6-4)/(-4-(-2)) = 2/-2 = -1
>b>Find the equation of the line that passes through the points (7,4) and (-5,-2).
slope is (-2-4)/(-5-7) = -6/-12 = 1/2
the point slope form gives
y-4 = 1/2 (x-7)
y = 1/2 x - 7/2 + 4
y = 1/2 x + 1/2
Find the equation of the line that passes through the points (1,4) and (2,-8).
slope = (-8-4)/(2-1) = -12/1 = -12
y-4 = 12(x-1)
y = 12x - 8
You got that one right.
Looks like you need to be more careful figuring your slopes.
Thank you and yes I honestly do... it's hard for me at least but I do try.
To find the slope of a line that passes through two points, you can use the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
For example, to find the slope of the line containing the points (3,2) and (1,-4), we can substitute the values into the formula:
m = (-4 - 2) / (1 - 3)
m = -6 / -2
m = 3
So, the slope of the line is 3.
Similarly, for the line containing the points (-2, 4) and (-4, 6), we have:
m = (6 - 4) / (-4 - (-2))
m = 2 / -2
m = -1
Therefore, the slope of this line is -1.
To find the equation of a line that passes through two points, you can use the point-slope form of the equation:
y - y1 = m(x - x1)
where (x1, y1) is one of the points on the line and m is the slope.
For the line passing through the points (7,4) and (-5,-2), we can use the slope we found previously, which is 3:
Using the point (7,4):
y - 4 = 3(x - 7)
y - 4 = 3x - 21
y = 3x - 17
So, the equation of the line that passes through these points is y = 3x - 17.
Similarly, for the line passing through the points (1,4) and (2,-8), we can use the slope we found, which is 12:
Using the point (1,4):
y - 4 = 12(x - 1)
y - 4 = 12x - 12
y = 12x - 8
Therefore, the equation of the line passing through these points is y = 12x - 8.