Two blocks,each of mass 3.0 kg are connected by a light cord and placed on a horizontal surfabe when a horizontal force of 20 newton is applied on a block an accn of 0.50 metre per second square is produced find(a)tensiom(b)force of friction which is same
net force=mass*acceleration
20N-friction=6kg*a
20=frictionforce=3
friction force=17N
Physics
To find the tension in the cord and the force of friction, we need to analyze the forces acting on each of the blocks separately.
First, let's consider the block to which the 20 Newton force is applied:
1. Apply Newton's second law of motion:
F = m * a
Here, the force, F = 20 Newtons
The acceleration, a = 0.50 m/s^2
The mass of the block, m = 3.0 kg
Substituting the values, we have:
20 = 3.0 * 0.50
Solving for the force, we get:
F = 1.5 Newtons
The force of 1.5 Newtons is the tension in the cord, and it acts in the direction of the applied force. Therefore, the tension in the cord is 1.5 Newtons.
Next, let's consider the other block:
2. The mass of the other block is also 3.0 kg.
Since the blocks are connected by a light cord, the tension in the cord applies the same force on both blocks.
Therefore, the force of friction acting on this block is also 1.5 Newtons, but in the opposite direction to the applied force.
Hence, to answer the given question:
a) The tension in the cord is 1.5 Newtons.
b) The force of friction acting on each block is also 1.5 Newtons.