A painter is placing a ladder to reach the third story window, which is 18 feet above the ground and makes an angle with the ground of 80°.
How far out from the building does the base of the ladder need to be positioned? Round your answer to the nearest tenth.
The base of the ladder needs to be positioned *how many*
feet out from the building.
* i just need the answer no work *
please help thanks (:
You are wasting your time and ours. Please take the course before you try to do the problems.
you can always get a book on geometry and study it. I learned calculus on my own from my teacher's textbook.
But I suggest you finish Algebra I before trying geometry or trig. It will give you a good foundation to work with.
To find the distance the base of the ladder needs to be positioned from the building, we can use trigonometry.
Since we have the height of the window, 18 feet, and the angle the ladder makes with the ground, 80°, we can use the sine function to find the distance.
The formula to find the distance is:
Distance = Height / sin(angle)
Plugging in the values, we have:
Distance = 18 / sin(80°)
Calculating this, we find that the distance is approximately 18.9 feet.
Therefore, the base of the ladder needs to be positioned approximately 18.9 feet out from the building.