How much heat is absorbed by a 30g iron skillet when its temperature rises from 24oC to 93oC?
Joules
do i addition everything?
heat=mass*specificheatIron*changeinTemp
To calculate the amount of heat absorbed by the iron skillet, you need to use the formula:
Q = mcΔT
Where:
Q - Heat absorbed (in Joules)
m - Mass of the skillet (in grams)
c - Specific heat capacity of the skillet material (in J/g°C)
ΔT - Change in temperature (in °C)
In this case, you have the mass of the skillet as 30g, the initial temperature as 24°C and the final temperature as 93°C.
You also need to know the specific heat capacity of iron, which is approximately 0.45 J/g°C.
Now, substitute the values into the formula:
Q = (30g) * (0.45 J/g°C) * (93°C - 24°C)
Now, subtract the initial temperature from the final temperature:
Q = (30g) * (0.45 J/g°C) * (69°C)
Q = 929.7 J
So, the amount of heat absorbed by the 30g iron skillet as its temperature rises from 24°C to 93°C is approximately 929.7 Joules.