If an Iron block had a length of 2 cm, and a width of 3 cm and a height of 1 cm and a mass of 33 g between what two liquids would it float?

To determine between which two liquids the iron block would float, we need to compare the density of the block with the densities of different liquids.

Density is defined as mass (m) divided by volume (V). In this case, we are given the mass of the iron block as 33 g. To find the volume of the block, we can use the formula for volume of a rectangular prism, which is length (l) multiplied by width (w) multiplied by height (h). In this case, the volume of the block would be 2 cm * 3 cm * 1 cm, which equals 6 cm³.

So, the density (d) of the iron block would be 33 g divided by 6 cm³, which is approximately 5.5 g/cm³.

Now, we need to compare this density with the densities of different liquids. Substances with lower density than the iron block will cause it to float, while substances with higher density will cause it to sink.

For example, the density of water is about 1 g/cm³, so the iron block with a density of 5.5 g/cm³ would sink in water. On the other hand, if we find a liquid with a density between 1 g/cm³ and 5.5 g/cm³, the iron block would float.

To determine the specific liquid between which the iron block would float, you would need to find liquids with densities between 1 g/cm³ and 5.5 g/cm³. You can search for the densities of various liquids and compare them to the density of the iron block. Typically, substances like oils, alcohols, or certain solutions can have different densities that fall within this range, but you would need to find specific liquids that match the required density range.