A guy travels to his home which takes 4 1/3hrs and a distance of 350km, he travels 60km/h for the first part and 90km/h for the rest of the journey.
Find:
An equation for the distance
An equation for the time
Detemine the distance he travelled for the first part and the rest of the journey
a. d = r*t.
b. t = d/t.
Eq1: t1 + t2 = 4 1/3 h. = 13/3 h.
Eq2: 60t1 + 90t2 = 350 km.
Solve the 2 Eqs simultaneously:
-60t1 - 60t2 = -260
+60t1 + 90t2 = 350
sum: 30t2 = 90, t2 = 3 h.
t1 + 3 = 13/3, t1 = 4/3 = 1 1/3 h.
d1 = 60 * 4/3 =
d2 = 90 * 3 =-