A space vehicle accelerates uniformly from 80 m/s at t = 0 to 165 m/s at t = 10.0 s .How far did it move between t = 2.0 s and t = 6.0 s ?

Averate speed=(165+80)/2=122.5 m/s

distance in four seconds:
d=avgspeed*time=122.5*4 m

To find the distance the space vehicle moved between t = 2.0 s and t = 6.0 s, we first need to calculate the displacement during that time interval.

The formula to calculate displacement using uniform acceleration is:

displacement = (final velocity - initial velocity) * time

Given:
Initial velocity (u) = 80 m/s
Final velocity (v) = 165 m/s
Time (t) = 6.0 s - 2.0 s = 4.0 s

Using the formula, we can calculate the displacement as follows:

displacement = (165 m/s - 80 m/s) * 4.0 s

Simplifying the equation:

displacement = 85 m/s * 4.0 s

displacement = 340 m

Therefore, the space vehicle moved a distance of 340 meters between t = 2.0 s and t = 6.0 s.