Calculate the molarity of 500.0 ml solution containing 26.5g Na2CO3
To calculate the molarity of a solution, you need to know the moles of solute and the volume of the solution in liters. The formula to calculate molarity is:
Molarity (M) = Moles of Solute / Volume of Solution (in liters)
To find the moles of Na2CO3, you need to use its molar mass. The molar mass of Na2CO3 can be calculated by summing up the atomic masses of its constituent elements: sodium (Na), carbon (C), and oxygen (O).
The atomic masses are:
- Na: 22.99 g/mol
- C: 12.01 g/mol
- O: 16.00 g/mol
Molar mass of Na2CO3 = (2 * Na) + C + (3 * O)
Molar mass of Na2CO3 = (2 * 22.99 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol)
Molar mass of Na2CO3 = 105.99 g/mol
Now, you can calculate the moles of Na2CO3 by dividing the given mass by its molar mass:
Moles of Na2CO3 = Mass of Na2CO3 / Molar mass of Na2CO3
Moles of Na2CO3 = 26.5 g / 105.99 g/mol
Moles of Na2CO3 ≈ 0.2498 mol
Next, you need to convert the given volume of the solution, 500.0 mL, to liters:
Volume of Solution = 500.0 mL / 1000 mL/L
Volume of Solution = 0.5000 L
Now, you have all the information needed to calculate the molarity:
Molarity (M) = Moles of Solute / Volume of Solution
Molarity (M) = 0.2498 mol / 0.5000 L
Molarity (M) ≈ 0.4996 mol/L
Therefore, the molarity of the solution containing 26.5g of Na2CO3 in 500.0 mL is approximately 0.4996 mol/L.