balanced equation for benzoic acid+alkaline KMnO4
To write a balanced equation for the reaction between benzoic acid (C6H5COOH) and alkaline KMnO4 (potassium permanganate), we need to follow a few steps:
Step 1: Identify the chemical formulas of all the reactants and products.
Benzoic acid: C6H5COOH
Alkaline KMnO4: KOH + KMnO4
Step 2: Identify the changes or reactions that occur.
In this case, the potassium permanganate (KMnO4) in an alkaline solution (KOH) acts as an oxidizing agent and oxidizes benzoic acid (C6H5COOH) to carbon dioxide (CO2) and manganese dioxide (MnO2).
Step 3: Write the balanced equation by ensuring that the number of atoms on both sides of the equation is equal.
The balanced equation for the reaction is:
C6H5COOH + 4 KOH + 2 KMnO4 → 6 CO2 + 2 MnO2 + K2CO3 + 3 H2O
Please note that this equation includes the products derived from the decomposition of potassium permanganate in an alkaline solution.
Now you have the balanced equation for the reaction between benzoic acid and alkaline KMnO4.