A stone is dropped from a height 80m calculate k.e and p.e at ts t 2 s
distance = 1/2 at^
a= 9.8 m/s/s. and t=2s
plug in and find the distance it has dropped.
subtract that distance from 80m to find the new height. PE = mgh, where h is the height.
Plug in and find PE
KE = 1/2 mv^2, so we need v after 2s
The equation is v= vo + at, and vo=0
So, v = 9.8(2). Multiply and find v
Plug v into the KE equation
This question can not be answered as you need to know the mass (or weight, since we're on earth) of the stone:
PE = mass x height x acceleration
KE = mass x velocity^2 / 2
To calculate the kinetic energy and potential energy of a stone at time t = 2 seconds after being dropped from a height of 80m, we need to use the formulas for potential energy (PE) and kinetic energy (KE).
The potential energy (PE) of the stone is given by the formula:
PE = m * g * h
where m is the mass of the stone, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.
The kinetic energy (KE) of the stone is given by the formula:
KE = (1/2) * m * v^2
where m is the mass of the stone, and v is its velocity.
Since we are not given the mass of the stone, we will assume it to be 1 kg for simplicity.
Step 1: Calculate the potential energy (PE) at t = 2 seconds:
PE = m * g * h
PE = 1 * 9.8 * 80
PE = 784 J
Step 2: Calculate the velocity of the stone at t = 2 seconds:
The velocity of a freely falling object can be calculated using the equation:
v = g * t
where g is the acceleration due to gravity and t is the time.
v = 9.8 * 2
v = 19.6 m/s
Step 3: Calculate the kinetic energy (KE) at t = 2 seconds:
KE = (1/2) * m * v^2
KE = (1/2) * 1 * (19.6)^2
KE = 191.6 J
Therefore, at t = 2 seconds, the potential energy (PE) of the stone is 784 J and the kinetic energy (KE) is 191.6 J.