A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 1 and 2. What is the probability that the third digit is 3? is it 1/7 or 1/6?
1/7
To determine the probability of the third digit being 3, we need to consider the total number of possible outcomes and the number of favorable outcomes where the third digit is 3.
Given that the first two digits are 1 and 2, we have two options for the first digit and one option for the second digit. This leaves us with 7 remaining digits (3, 4, 5, 6, 7, 8, and 9) for the third digit.
To calculate the probability, we need to find the number of favorable outcomes (where the third digit is 3) and divide it by the total number of possible outcomes.
Since there is only one favorable outcome (the third digit being 3), and there are seven possible outcomes for the third digit, the probability of the third digit being 3 is 1/7.
So, the correct answer is 1/7.