A man is standing on a platform that is connected to a pulley arrangement, as the drawing shows. By pulling upward on the rope with a force   the man can raise the platform and himself. The total mass of the man plus the platform is 121 kg. What pulling force should the man apply to create an upward acceleration of 1.20 m/s2?

the first thing you always want to do is drawing a free body diagram, you see that there is only 2 vertical forces and no horizontal forces. the +P force & the -W force. Always find your equation symbolically first, using ΣF=MA, 1. P-W=MA, 2. P-MG (since w=mg)=MA, (youre solving for p so add -MG to MA) 3. P=MA+MG or P=M(A+G) 4. plug in numbers P=(121.0 kg)(1.20 m/s^2 + 9.81 m/s^2) 5. P=1332.21 N.

Why did the platform become friends with the pulley arrangement? Because they had so much in tension!

Ahem, let's calculate the pulling force needed, shall we? According to Newton's second law, the force (F) required to create an upward acceleration (a) is given by the equation F = m * a, where m is the mass of the man plus the platform.

Given that the total mass (m) is 121 kg and the upward acceleration (a) is 1.20 m/s², we simply need to substitute those values into the equation:

F = (121 kg) * (1.20 m/s²)

Calculating that gives us F = 145.2 N.

So, the man needs to apply a pulling force of 145.2 Newtons to give himself and the platform an upward acceleration of 1.20 m/s². Although, I hope he doesn't end up pulling the platform's leg!

To find the pulling force that the man should apply to create an upward acceleration of 1.20 m/s^2, we need to apply Newton's second law of motion, which states that the force applied is equal to the mass multiplied by the acceleration:

Force = mass * acceleration

In this case, the total mass of the man plus the platform is given as 121 kg, and the upward acceleration is given as 1.20 m/s^2. Therefore, we can substitute these values into the formula:

Force = 121 kg * 1.20 m/s^2

Multiplying these values together, we get:

Force = 145.2 kg•m/s^2

This is the force that the man should apply to create an upward acceleration of 1.20 m/s^2. Therefore, the pulling force should be 145.2 N (Newton) in the upward direction.

Total mass:-121kg

Acceleration:-1.20
Force:-?
:-Using formula F=MA
whe have:-121*1.20=145.2Ans
to Check:-F=MA making A subject formula we have:-
A=F/M which gives us
145.2/121=1.20
:-The Total mass 121kg with the acceleration 1.20 will need a total force of 145.2

Total mass:-121kg

Acceleration:-1.20
Force:-?
:-Using formula we have F=MA
F=121*1.20=145.2Ans
to check:-F=MA
:-making a subject of formula
A=F/M 145.2/121=1.20
:-The total mass 121kg with acceleration 1.20 will need a force of 145.2